We use cookies to give you the best experience possible. By continuing we’ll assume you’re on board with our cookie policy

A Redox Titration between Manganate (VII) and Iron (II) Essay Sample

essay
  • Pages: 7
  • Word count: 1,694
  • Rewriting Possibility: 99% (excellent)
  • Category: solutions

Get Full Essay

Get access to this section to get all help you need with your essay and educational issues.

Get Access

Introduction of TOPIC

Objective:

To determine the x in the formula Fe (NH4)2(SO4)2�xH2O by titration against a standard solution of potassium manganate (VII) (permanganate).

Theory:

The experiment involves a redox reaction between potassium manganate (VII) and ammonium

Potassium manganate (VII) is used in the experiment as it reacts completely and it is its own indicator. Potassium manganate (VII) solution is a strong oxidizing agent. In an acidic medium, manganate(VII) ion undergoes reduction as shown below.

MnO4- (aq) + 8H+ (aq) + 5e- –> 4H2O (l) + Mn2+ (aq)

Ammonium Iron (II) sulphate is a strong reducing agent because of the presence of Iron (II) ions. Iron (II) ions can be oxidized to form Fe3+ which is yellow in color.

Manganate (VII) ions are purple in color, when the MnO4- are reduced to Mn 2+, the color of the solution becomes pale pink, thus a self indicating titration can occur

According to the overall reaction:

MnO4- (aq) + 5Fe 2+ (aq) +8H+(aq) –> Mn2+(aq) +5Fe3+(aq)+4H2O(l)

Between the titration of potassium manganate (VII) solution and ammonium iron (II) sulphate solution, The molarity of ammonium iron (II)

Apparatus:

Safety spectacles

25cm3 pipette

Pipette filler

4 conical flasks

50cm3 burette

Small funnel

White tile

Wash-bottle of distilled water

Materials

Solution A: ammonium Iron(II) sulphate solution

1M dilute sulphuric acid

Solution B: potassium manganate (VII)

Procedures:

1. The burette was filled with potassium manganate (VII) solution B

2. 25 cm3of the ammonium iron (II) sulphate solution A into was pipette into a conical flask.

3. 25 cm3of the dilute sulphuric acid was added into the conical flask filled with 25 cm3of ammonium iron (II) sulphate solution A

4. The conical flask was titrated with potassium permanganate solution B

5. The titration was stopped when a pale pink colour was formed in the conical flask

6. The titration was repeated several times to obtain consistent results

7.

Result

Concentration of potassium manganate (VII) solution, B: 0.0189 ( mol dm3)

Concentration of ammonium iron (II) sulphate solution, A: 39.214 (g dm3)

Trial

1

2

3

4

Final Burette reading(cm3)

38.7

40.3

38.3

39.6

39.3

Initial Burette reading (cm3)

12.5

14.2

12.2

13.7

13.2

Volume used (cm3)

26.2

26.1

26.1

25.9

26.1

Average volume used :

26.1 + 26.1 + 25.9 + 26.1 = 26.05 cm3

4

Calculation:

MnO4- (aq) + 5Fe 2+ (aq) +8H+(aq) –> Mn2+(aq) +5Fe3+(aq)+4H2O(l)

We can find the no. of moles of MnO4- by:

0.0189 � 26.05 = 4.293 � 10-4

>1000 According to the equation above, 1 mol of MnO4- react with

Sorry, but full essay samples are available only for registered users

Choose a Membership Plan
5 moles of Fe 2+

So, the no of moles of Fe 2+ is :

4.293 � 10-3� 5 = 2.46� 10-3

By the finding the no of moles of Fe 2+, we can find the Molarity by using the formula,

Molarity = No of moles

Volume

Molarity of Fe 2+ = 2.46� 10-3

25/1000

= 0.0985 mol dm-3

By finding the Molarity we can find the mass of anhydrous Fe (NH4)2(SO4)2 in one dm3.

Molar mass of Fe (NH4)2(SO4)2 = 55.8+ (14.0+4) + (32.1 + 16�4) �2

= 55.8+ 36+192.2

= 284 g mol

Molarity of Fe 2+ = molarity of Fe (NH4)2(SO4)2

Therefore, Molarity of Fe (NH4)2(SO4)2 = 0.0985 mol dm-3

The No of moles of Fe (NH4)2(SO4)2 can be found by the formula:

Molarity � Volume = no of moles

0.0985 � 1 dm-3 = 0.0985 moles

Therefore the no of moles of Fe (NH4)2(SO4)2 is 0.0985 moles.

The mass of anhydrous Fe (NH4)2(SO4)2 can be found by:

0.0985 mol � 284 g mol = 27.97g

Therefore the mass of anhydrous Fe (NH4)2(SO4)2 in 1 dm-3 is 28 g.

Using the concentration of ammonium iron (II) sulphate solution and the mass of anhydrous Fe (NH4)2(SO4)2 we can obtain volume of the Fe (NH4)2(SO4)2�xH2O

Let the volume of the solution of ammonium iron (II) sulphate be V:

39.214 g dm-3 = 27.97g

V

39.214 g dm-3 V= 27.97

V= 0.7132 dm-3

The no of moles of Fe (NH4)2(SO4)2�xH2O can be found by the formula:

Molarity � Volume = no of moles

The Molarity of Fe (NH4)2(SO4)2�xH2O= Molarity of Fe 2+

0.0985mol dm3� 0.7132 dm3 = 0.703mol

Therefore the no of moles of Fe (NH4)2(SO4)2�xH2O is 0.0703mol

The molar mass of Fe (NH4)2(SO4)2�xH2O Can be found by:

Let the molar mass of Fe (NH4)2(SO4)2�xH2O be MM

27.97 = 0.0703

MM

27.97=0.0703MM

MM= 398.1

Therefore the total molar mass Fe (NH4)2(SO4)2�xH2O is 398.

The Molar mass of Fe (NH4)2(SO4)2�xH2O is :

284+x(2+16)

= 284 + 18x

By using the total molar mass:

284 + 18x = 398

18x= 398-284

18x= 114

x=6.33

x=6

Therefore the value of x is 6.

Therefore the formula is Fe (NH4)2(SO4)2�6H2O.

Discussion:

A redox titration involves a reducing agent and an oxidizing agent. In this experiment, ammonium iron (II) sulphate was the reducing agent and potassium manganate was the oxidizing agent.

Observations:

The solution in the conical flask was titrated with potassium permanganate, the solution in the flask first turn into a yellowish colour; this was because of the formation of Iron (III) ions formed during the redox reaction.

According to the following equation:

Fe 2+ (aq)+ e—> Fe3+(aq)

The formation of Fe3+ caused the solution to turn yellow when it was titrated against the potassium manganate (VII).

Solution gradually turned into pale pink because of the formation of Mn2+

The excess Mn2+ caused the solution to turn to pale pink. According to the eqation.

MnO4- (aq) + 8H+ (aq) + 5e- –> 4H2O (l) + Mn2+ (aq)

Questions:

1. Explain why it is unnecessary to use any indicator in this experiment.

–>This is because potassium permanganate can be its own self indicator because it can form a pale pink colour due to the formation of Mn2+ when it is being reduced

2. Explain why dilute sulphuric acid should be added to ammonium iron (II) sulphate solution before titration.

–> It prevents premature oxidation of iron (II) ions as hydrated ammonium iron (II) ions may react with air to form Iron (III) ions.

It also ensures the complete reaction for manganate from manganate (VII) to Mn2+

2. Suggest one possible error in the experiment

–> The possible error of this experiment is that maybe the pipette was not washed properly as the same pipette was used to pipette 25cm3 of ammonium iron (II) sulphate and 25cm3 of sulphuric acid. The solution could have already reacted when pipette.

Conclusion:

The value of x in the formula of Fe (NH4)2(SO4)2�xH2O is 6.

We can write a custom essay on

A Redox Titration between Manganate (VII) and Iron ...
According to Your Specific Requirements.

Order an essay

You May Also Find These Documents Helpful

Ammonium hydroxide solution

In the strong acid-weak base titration, 0. 1 M ammonium hydroxide ( NH4OH ) was titrated with 0. 1 M hydrochloric acid ( HCl ). 2-3 drops of phenolphthalein were added as indicator into the conical flask which contains 25mL of hydrochloric acid. Ammonium hydroxide was then titrated slowly into the conical flask and the conical flask was swirled gently to ensure the reaction is reacted completely. The titration stops when the colour of the titrand changed from colourless to pale pink. The average titrant (29. 55 mL) of 0. 1 M of ammonium hydroxide was added into the conical flask. By using screened methyl orange as indicator, the average titrant (26. 45 mL) of 0. 1 M of ammonium hydroxide was added to change the colour of the titrand from red to grey in conical flask. In weak acid-strong base titration, 0. 1 M sodium hydroxide ( NaOH )...

The concentration of nitrate ion in a...

Chemically modi? ed polymeric adsorbents are resins with functional groups such as phenolic hydroxyl, acetyl, sulfonic group or amino group, grafted on hyper cross linked polymers (Alexandratos & Natesan 1999), (Cai et al. 2005). Among these, aminated hyper cross linked polymers display a unique advantage in adsorption of aromatic sulphonates (Pan et al. 2005) phenol derivatives (Pan, Zhang, Wei & Ren 2008), and phenolic acids (Wang, Zhang, Zhao, Xia, & Chen 2005) due to the presence of electrostatic interactions, hydrogen bonding interaction or interaction between adsorbents and adsorbents. Polystyrene particles have excellent chemical and physical properties that make them not easy to be degraded and damaged. Therefore polystyrene based adsorbents are usually used repeatedly. Unmodified particles are not suitable to adsorb substances from aqueous solutions because the surface is hydrophobic and lack of selective groups (Wang et al. 2005). However their hydrophobicity and selectivity is increased after modification. Nitrate is...

Using Hess's Law to Calculate Enthalpy Change

Controlled variables: - Mass of water - Mass of magnesium sulphate anhydrous - Mass of MgSO4.7H20 Materials: 1) Safety spectacles 2) 2 filter papers 3) Spatula 4) Digital balance 5) 2 polystyrene cups 6) Thermometer 7) Magnesium sulphate anhydrous 8) Magnesium sulphate-7- water 9) Distilled water 10) Measuring cylinder Procedure: Part A 1) Weigh 3.01g of MgSO4 anhydrous to the nearest 0.01g on a filter paper, using the digital balance. 2) Weigh 45.00g of water to the nearest 0.01g into a polystyrene cup using the balance. 3) Measure the initial temperature of the measured amount of water using the thermometer and record this value. 4) Add the measured amount of MgSO4 anhydrous to the water and stir. Measure and record the maximum temperature obtained using the thermometer. Part B 1) Weigh 6.16g of MgSO4.7H20 to the nearest 0.01g on a filter paper, using the digital balance. 2) Weigh 41.85g of...

Popular Essays

logo

Emma Taylor

online

Hi there!
Would you like to get such a paper?
How about getting a customized one?